Option 4 : 1.0fA

CT 3: Building Materials

3014

10 Questions
20 Marks
12 Mins

**Explanation**

Since the equal angle of the area, A has been attached, then the area of each leg = A_{1} = A_{2} = A/2

The load-carrying capacity of the angle is dependent upon the net effective area, which can be written as

A_{net} = A_{1} + K × A_{2}

**Note**

In the case of lug angles,

k = 1

Effective area = \(\frac{A}{2} + {1} \times \frac{A}{2} = {A} = A\)

Therefore, load-carrying capacity of the member = A × f = 1fA